Optimal. Leaf size=206 \[ -\frac {3}{2} b^2 \text {Li}_3\left (1-\frac {2}{i c x+1}\right ) \left (a+b \tan ^{-1}(c x)\right )+\frac {3}{2} b^2 \text {Li}_3\left (\frac {2}{i c x+1}-1\right ) \left (a+b \tan ^{-1}(c x)\right )-\frac {3}{2} i b \text {Li}_2\left (1-\frac {2}{i c x+1}\right ) \left (a+b \tan ^{-1}(c x)\right )^2+\frac {3}{2} i b \text {Li}_2\left (\frac {2}{i c x+1}-1\right ) \left (a+b \tan ^{-1}(c x)\right )^2+2 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^3+\frac {3}{4} i b^3 \text {Li}_4\left (1-\frac {2}{i c x+1}\right )-\frac {3}{4} i b^3 \text {Li}_4\left (\frac {2}{i c x+1}-1\right ) \]
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Rubi [A] time = 0.43, antiderivative size = 206, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {4850, 4988, 4884, 4994, 4998, 6610} \[ -\frac {3}{2} b^2 \text {PolyLog}\left (3,1-\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )+\frac {3}{2} b^2 \text {PolyLog}\left (3,-1+\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )-\frac {3}{2} i b \text {PolyLog}\left (2,1-\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^2+\frac {3}{2} i b \text {PolyLog}\left (2,-1+\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^2+\frac {3}{4} i b^3 \text {PolyLog}\left (4,1-\frac {2}{1+i c x}\right )-\frac {3}{4} i b^3 \text {PolyLog}\left (4,-1+\frac {2}{1+i c x}\right )+2 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^3 \]
Antiderivative was successfully verified.
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Rule 4850
Rule 4884
Rule 4988
Rule 4994
Rule 4998
Rule 6610
Rubi steps
\begin {align*} \int \frac {\left (a+b \tan ^{-1}(c x)\right )^3}{x} \, dx &=2 \left (a+b \tan ^{-1}(c x)\right )^3 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )-(6 b c) \int \frac {\left (a+b \tan ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx\\ &=2 \left (a+b \tan ^{-1}(c x)\right )^3 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )+(3 b c) \int \frac {\left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx-(3 b c) \int \frac {\left (a+b \tan ^{-1}(c x)\right )^2 \log \left (2-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx\\ &=2 \left (a+b \tan ^{-1}(c x)\right )^3 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )-\frac {3}{2} i b \left (a+b \tan ^{-1}(c x)\right )^2 \text {Li}_2\left (1-\frac {2}{1+i c x}\right )+\frac {3}{2} i b \left (a+b \tan ^{-1}(c x)\right )^2 \text {Li}_2\left (-1+\frac {2}{1+i c x}\right )+\left (3 i b^2 c\right ) \int \frac {\left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx-\left (3 i b^2 c\right ) \int \frac {\left (a+b \tan ^{-1}(c x)\right ) \text {Li}_2\left (-1+\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx\\ &=2 \left (a+b \tan ^{-1}(c x)\right )^3 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )-\frac {3}{2} i b \left (a+b \tan ^{-1}(c x)\right )^2 \text {Li}_2\left (1-\frac {2}{1+i c x}\right )+\frac {3}{2} i b \left (a+b \tan ^{-1}(c x)\right )^2 \text {Li}_2\left (-1+\frac {2}{1+i c x}\right )-\frac {3}{2} b^2 \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_3\left (1-\frac {2}{1+i c x}\right )+\frac {3}{2} b^2 \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_3\left (-1+\frac {2}{1+i c x}\right )+\frac {1}{2} \left (3 b^3 c\right ) \int \frac {\text {Li}_3\left (1-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx-\frac {1}{2} \left (3 b^3 c\right ) \int \frac {\text {Li}_3\left (-1+\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx\\ &=2 \left (a+b \tan ^{-1}(c x)\right )^3 \tanh ^{-1}\left (1-\frac {2}{1+i c x}\right )-\frac {3}{2} i b \left (a+b \tan ^{-1}(c x)\right )^2 \text {Li}_2\left (1-\frac {2}{1+i c x}\right )+\frac {3}{2} i b \left (a+b \tan ^{-1}(c x)\right )^2 \text {Li}_2\left (-1+\frac {2}{1+i c x}\right )-\frac {3}{2} b^2 \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_3\left (1-\frac {2}{1+i c x}\right )+\frac {3}{2} b^2 \left (a+b \tan ^{-1}(c x)\right ) \text {Li}_3\left (-1+\frac {2}{1+i c x}\right )+\frac {3}{4} i b^3 \text {Li}_4\left (1-\frac {2}{1+i c x}\right )-\frac {3}{4} i b^3 \text {Li}_4\left (-1+\frac {2}{1+i c x}\right )\\ \end {align*}
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Mathematica [A] time = 0.15, size = 212, normalized size = 1.03 \[ \frac {3}{4} i b \left (2 \text {Li}_2\left (\frac {c x+i}{i-c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^2-2 \text {Li}_2\left (\frac {c x+i}{c x-i}\right ) \left (a+b \tan ^{-1}(c x)\right )^2+b \left (-2 i \text {Li}_3\left (\frac {c x+i}{i-c x}\right ) \left (a+b \tan ^{-1}(c x)\right )+2 i \text {Li}_3\left (\frac {c x+i}{c x-i}\right ) \left (a+b \tan ^{-1}(c x)\right )+b \left (\text {Li}_4\left (\frac {c x+i}{c x-i}\right )-\text {Li}_4\left (\frac {c x+i}{i-c x}\right )\right )\right )\right )+2 \tanh ^{-1}\left (\frac {c x+i}{c x-i}\right ) \left (a+b \tan ^{-1}(c x)\right )^3 \]
Antiderivative was successfully verified.
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fricas [F] time = 0.42, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b^{3} \arctan \left (c x\right )^{3} + 3 \, a b^{2} \arctan \left (c x\right )^{2} + 3 \, a^{2} b \arctan \left (c x\right ) + a^{3}}{x}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.24, size = 2309, normalized size = 11.21 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ a^{3} \log \relax (x) + \frac {1}{32} \, \int \frac {28 \, b^{3} \arctan \left (c x\right )^{3} + 3 \, b^{3} \arctan \left (c x\right ) \log \left (c^{2} x^{2} + 1\right )^{2} + 96 \, a b^{2} \arctan \left (c x\right )^{2} + 96 \, a^{2} b \arctan \left (c x\right )}{x}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (a+b\,\mathrm {atan}\left (c\,x\right )\right )}^3}{x} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \operatorname {atan}{\left (c x \right )}\right )^{3}}{x}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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